UNED A25 - 2013 Junio Modelo A Ejercicio 3

Calcular \left(
\begin{array}{cc}
1 & 2
\\ 1 & -1
\end{array}
\right)
\cdot
\left(
\begin{array}{ccc}
0 & 1 & -1
\\ 1 & 1 & 0
\end{array}
\right)

SOLUCIÓN

\left(
\begin{array}{cc}
1 & 2
\\ 1 & -1
\end{array}
\right)
\cdot
\left(
\begin{array}{ccc}
0 & 1 & -1
\\ 1 & 1 & 0
\end{array}
\right) = \left(
\begin{array}{ccc}
2 & 3 & -1
\\ -1 & 0 & -1
\end{array}
\right)