$-2 \cdot (3-4i)=(-2) \cdot 3 + (-2) \cdot (-4i)= -6+8i$ $(2-3i) + (-5-7i)=2-3i -5-7i = -3-10i$ $(3+5i) - (4-6i)= 3+5i-4+6i= -1+11i$ $(3+2i) \cdot (3-2i)=3^2 - (2i)^2 = 9 - 4i^2 = 9-4 \cdot (-1) =9+4=13 $ $\frac3-2i4+3i = \frac(3-2i) \cdot (4-3i)(4+3i) \cdot (4-3i) = $
$\frac3 \cdot 4 + 3 (…)