2011-05-27T11:06:58Z https://matematicasies.com/ecuaciones-grado1-parentesis-27#comment314 2011-05-27T11:06:58Z

<p>quisiera saber como han hecho para el resultado de esa fraccion;<br class="autobr"> (2*1/2)= 1-1 <br><span class="spip-puce ltr"><b>–</b></span> 5+1/2=-9/2</p>

2007-08-18T15:24:38Z https://matematicasies.com/ecuaciones-grado1-parentesis-27#comment211 2007-08-18T15:24:38Z

<p>Veamos que la solución <img src='https://matematicasies.com/local/cache-TeX/8252d77bf5b096d504816a5094724abd.png' style="vertical-align:middle;" width="52" height="65" alt="x=\frac{1}{2}" title="x=\frac{1}{2}"> verifica la ecuación:<br> Para ello sustituimos en la ecuación <img src='https://matematicasies.com/local/cache-TeX/9dd4e461268c8034f5c8564e155c67a6.png' style="vertical-align:middle;" width="17" height="30" alt="x" title="x"> por el valor <img src='https://matematicasies.com/local/cache-TeX/93b05c90d14a117ba52da1d743a43ab1.png' style="vertical-align:middle;" width="15" height="65" alt="\frac{1}{2}" title="\frac{1}{2}"><br></p> <p><img src='https://matematicasies.com/local/cache-TeX/de841b685bbdca09f49145dad716d380.png' style="vertical-align:middle;" width="273" height="42" alt="4(2x-1)+15=6-2(-5+x)" title="4(2x-1)+15=6-2(-5+x)"></p> <p>Sustituimos <img src='https://matematicasies.com/local/cache-TeX/9dd4e461268c8034f5c8564e155c67a6.png' style="vertical-align:middle;" width="17" height="30" alt="x" title="x"> por <img src='https://matematicasies.com/local/cache-TeX/93b05c90d14a117ba52da1d743a43ab1.png' style="vertical-align:middle;" width="15" height="65" alt="\frac{1}{2}" title="\frac{1}{2}"></p> <p><img src='https://matematicasies.com/local/cache-TeX/85a20f5f8b030de2f63dd560dec51353.png' style="vertical-align:middle;" width="328" height="65" alt="4 \left(2 \cdot \frac{1}{2}-1 \right)+15=6-2 \cdot \left(-5+\frac{1}{2} \right)" title="4 \left(2 \cdot \frac{1}{2}-1 \right)+15=6-2 \cdot \left(-5+\frac{1}{2} \right)"></p> <p>Operamos dentro de los paréntesis y sin olvidar la prioridad de las operaciones (productos antes que sumas o restas)</p> <p><img src='https://matematicasies.com/local/cache-TeX/bf662ab50ca7ab92f7d3757e3f17833d.png' style="vertical-align:middle;" width="268" height="65" alt="4 \cdot (1-1)+15=6-2 \cdot \left(\frac{-9}{2} \right)" title="4 \cdot (1-1)+15=6-2 \cdot \left(\frac{-9}{2} \right)"></p> <p><img src='https://matematicasies.com/local/cache-TeX/f1039289b251653a282c9971269b5ca0.png' style="vertical-align:middle;" width="220" height="65" alt="4 \cdot 0 +15 = 6-2 \cdot \left(\frac{-9}{2} \right)" title="4 \cdot 0 +15 = 6-2 \cdot \left(\frac{-9}{2} \right)"></p> <p><img src='https://matematicasies.com/local/cache-TeX/6768010af8a7ea9d3c407c113cd586dc.png' style="vertical-align:middle;" width="195" height="65" alt="0 +15 = 6-2 \cdot \left(\frac{-9}{2}\right)" title="0 +15 = 6-2 \cdot \left(\frac{-9}{2}\right)"></p> <p><img src='https://matematicasies.com/local/cache-TeX/5a7cafdfb444b74439afd916f2d1ee43.png' style="vertical-align:middle;" width="127" height="38" alt="0 +15 = 6 + 9" title="0 +15 = 6 + 9"></p> <p><img src='https://matematicasies.com/local/cache-TeX/d7c5bcf4cd69ada5ebdc069d48ba6a91.png' style="vertical-align:middle;" width="68" height="38" alt="15 = 15" title="15 = 15"></p> <p>La igualdad <img src='https://matematicasies.com/local/cache-TeX/d7c5bcf4cd69ada5ebdc069d48ba6a91.png' style="vertical-align:middle;" width="68" height="38" alt="15 = 15" title="15 = 15"> es cierta, por tanto la solución <img src='https://matematicasies.com/local/cache-TeX/8252d77bf5b096d504816a5094724abd.png' style="vertical-align:middle;" width="52" height="65" alt="x=\frac{1}{2}" title="x=\frac{1}{2}"> es correcta</p>

2006-06-15T00:11:15Z https://matematicasies.com/ecuaciones-grado1-parentesis-27#comment11 2006-06-15T00:11:15Z

<p> </p><p class="spip" style="text-align:center;"><img src='https://matematicasies.com/local/cache-TeX/de841b685bbdca09f49145dad716d380.png' style="vertical-align:middle;" width="273" height="42" alt="4(2x-1)+15=6-2(-5+x)" title="4(2x-1)+15=6-2(-5+x)"></p> <br class="autobr"> <p class="spip" style="text-align:center;"><img src='https://matematicasies.com/local/cache-TeX/62027c9e572f8e7e66b308e0f8eefaae.png' style="vertical-align:middle;" width="228" height="38" alt="8x-4+15=6+10-2x" title="8x-4+15=6+10-2x"></p> <br class="autobr"> <p class="spip" style="text-align:center;"><img src='https://matematicasies.com/local/cache-TeX/8b229c13fb19afd083ebca1f2af17078.png' style="vertical-align:middle;" width="227" height="38" alt="8x+2x = 6 + 10 + 4 - 15" title="8x+2x = 6 + 10 + 4 - 15"></p> <br class="autobr"> <p class="spip" style="text-align:center;"><img src='https://matematicasies.com/local/cache-TeX/961fa33b843938d24a49252f5ca7ebe5.png' style="vertical-align:middle;" width="70" height="38" alt="10x = 5" title="10x = 5"></p> <br class="autobr"> <p class="spip" style="text-align:center;"><img src='https://matematicasies.com/local/cache-TeX/b5dd1978c7e7ebb06d6a130349ca7fc0.png' style="vertical-align:middle;" width="102" height="65" alt="x = \frac{5}{10} = \frac{1}{2}" title="x = \frac{5}{10} = \frac{1}{2}"></p> <br class="autobr">