2012-03-14T13:08:04Z https://matematicasies.com/ecuaciones-primer-grado-con-denominadores#comment909 2012-03-14T13:08:04Z

<p>Hay otras formas de acerlo y ahora nose si lo tengo bien o mal :((</p>

2007-08-19T15:03:48Z https://matematicasies.com/ecuaciones-primer-grado-con-denominadores#comment213 2007-08-19T15:03:48Z

<p>Resolvemos la ecuación <img src='https://matematicasies.com/local/cache-TeX/6a78e1f8c770d36a0e5d9b2612affcbb.png' style="vertical-align:middle;" width="168" height="65" alt="\frac{x-6}{3}+2=\frac{4x-1}{5}" title="\frac{x-6}{3}+2=\frac{4x-1}{5}"> <br><img src='https://matematicasies.com/local/cache-TeX/f502aef29c133da099920f104e04fa7f.png' style="vertical-align:middle;" width="170" height="42" alt="m.c.m.(3,1,5)=15" title="m.c.m.(3,1,5)=15"> <br><img src='https://matematicasies.com/local/cache-TeX/dcd5a0c05953bc16658462ac68fb6706.png' style="vertical-align:middle;" width="258" height="70" alt="\frac{5(x-6)}{15}+\frac{15 \cdot 2}{15}=\frac{3(4x-1)}{15}" title="\frac{5(x-6)}{15}+\frac{15 \cdot 2}{15}=\frac{3(4x-1)}{15}"> <br><img src='https://matematicasies.com/local/cache-TeX/e3428c4e29a5e65fc34969c546515bd1.png' style="vertical-align:middle;" width="247" height="42" alt="5(x-6)+15 \cdot 2=3(4x-1)" title="5(x-6)+15 \cdot 2=3(4x-1)"> <br><img src='https://matematicasies.com/local/cache-TeX/7ddf17756b5d6a3b46c0478bfc51c929.png' style="vertical-align:middle;" width="203" height="38" alt="5x-30 + 30 = 12x -3" title="5x-30 + 30 = 12x -3"> <br><img src='https://matematicasies.com/local/cache-TeX/f2a102238e803d0ba4e72192fc57701a.png' style="vertical-align:middle;" width="130" height="38" alt="5x - 12x = -3" title="5x - 12x = -3"> <br><img src='https://matematicasies.com/local/cache-TeX/f45da1e2b116d1b6a6c17a1ed664093e.png' style="vertical-align:middle;" width="92" height="38" alt="-7x = -3" title="-7x = -3"> <br><img src='https://matematicasies.com/local/cache-TeX/45e9cc35020b340396cdf1c0e60ee4ea.png' style="vertical-align:middle;" width="108" height="65" alt="x = \frac{-3}{-7} = \frac{3}{7}" title="x = \frac{-3}{-7} = \frac{3}{7}"></p> <p>Aunque en estas ecuaciones no es obligatorio verificar las soluciones, resulta<br class="autobr"> un práctico y didáctico ejercicio su comprobación</p> <p><img src='https://matematicasies.com/local/cache-TeX/cb190bc90022e790079f4e4289561cf4.png' style="vertical-align:middle;" width="185" height="73" alt="\frac{\frac{3}{7}-6}{3}+2=\frac{4 \cdot \frac{3}{7}-1}{5}" title="\frac{\frac{3}{7}-6}{3}+2=\frac{4 \cdot \frac{3}{7}-1}{5}"> <br><img src='https://matematicasies.com/local/cache-TeX/945d0a254049953f400db55b43d13537.png' style="vertical-align:middle;" width="152" height="73" alt="\frac{\frac{-39}{7}}{3}+2=\frac{\frac{12}{7}-1}{5}" title="\frac{\frac{-39}{7}}{3}+2=\frac{\frac{12}{7}-1}{5}"> <br><img src='https://matematicasies.com/local/cache-TeX/8892bed1ed25facc8c0b06d24f48ca3e.png' style="vertical-align:middle;" width="115" height="73" alt="\frac{-39}{21}+2=\frac{\frac{5}{7}}{5}" title="\frac{-39}{21}+2=\frac{\frac{5}{7}}{5}"> <br><img src='https://matematicasies.com/local/cache-TeX/9dd27546cbc41a4252011afeabec693a.png' style="vertical-align:middle;" width="75" height="65" alt="\frac{3}{21}=\frac{5}{35}" title="\frac{3}{21}=\frac{5}{35}"> <br>Simplificamos ambas fracciones <br><img src='https://matematicasies.com/local/cache-TeX/4dbcee2b7f7e2f389cb1ba3ea0c12bb1.png' style="vertical-align:middle;" width="55" height="65" alt="\frac{1}{7}=\frac{1}{7}" title="\frac{1}{7}=\frac{1}{7}"> <br>La igualdad obtenida es cierta, por tanto la solución es correcta</p>