Vemos que $X \longrightarrow N(161, 16)$
a) $P(X \geq 180) = P\left(Z \geq \frac180-16116\right)=P\geft(Z \geq 1.18\right)= 1- P\left(Z \leq 1.18\right)=1- 0.8810=0.119$
b) $P(X \geq 200) = P\left(Z \geq \frac200-16116\right)=P\geft(Z \geq 2.44\right)= 1- P\left(Z \leq 2.44\right)=1- (…)