$$4\cdot\sqrtx-2=x+2 $$ $$\left(4\cdot\sqrtx-2\right)^2=(x+2)^2 $$ $$4^2 \cdot \left(\sqrtx-2\right)^2=(x+2)^2 $$ $$16 \cdot (x-2)=x^2+2^2 + 2 \cdot 2 \cdot x $$ $$16x-32=x^2+4 + 4x $$ $$-x^2+12x-36=0 $$ $$ \beginarrayccc & & x_1 = \frac-12+0-2=6\ & \nearrow &\ x=\frac-12\pm (…)