UNED A25 - 2013 Junio Modelo A Ejercicio 3

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Calcular
\left( \begin{array}{cc} 1 & 2 \\ 1 & -1 \end{array} \right) \cdot \left( \begin{array}{ccc} 0 & 1 & -1 \\ 1 & 1 & 0 \end{array} \right)

SOLUCIÓN

\left( \begin{array}{cc} 1 & 2 \\ 1 & -1 \end{array} \right) \cdot \left( \begin{array}{ccc} 0 & 1 & -1 \\ 1 & 1 & 0 \end{array} \right) = \left( \begin{array}{ccc} 2 & 3 & -1 \\ -1 & 0 & -1 \end{array} \right)