radicales

, por dani

| 1 |

\frac{\sqrt{2} \cdot \sqrt{8} \cdot \sqrt{3}}{\sqrt{6}} =
\frac{\sqrt{2} \cdot \sqrt{8} \cdot \sqrt{3}}{\sqrt{2} \cdot \sqrt{3}} =
\frac{\cancel{\sqrt{2}} \cdot \sqrt{8} \cdot \cancel{\sqrt{3}}}{\cancel{\sqrt{2}} \cdot \cancel{\sqrt{3}}} =
\sqrt{8}=\sqrt{2^3}=2 \sqrt{2}

Calcula y simplifica:

\frac{\sqrt{2} \cdot \sqrt{8} \cdot \sqrt{3}}{\sqrt{6}}