Matemáticas IES
radicales simplificar
– a) ![\sqrt[4]{2^8}=\sqrt[4]{2^4 \cdot 2^4} = 2 \cdot 2=4](local/cache-vignettes/L232xH52/412d719e064213c6b8e71b3d86f18229-a3473.png?1688052540 "\sqrt[4]{2^8}=\sqrt[4]{2^4 \cdot 2^4} = 2 \cdot 2=4")
– b) ![\sqrt[3]{1000}=\sqrt[3]{10^3}=10](local/cache-vignettes/L180xH52/09123b220a350140c9a9751bf220e624-3f55c.png?1688052540 "\sqrt[3]{1000}=\sqrt[3]{10^3}=10")
– c) ![\sqrt[6]{12}](local/cache-vignettes/L43xH50/35f5365ff45a53b2dabb1cf904434a72-e805c.png?1688052540 "\sqrt[6]{12}"){kind=small}
– d) ![\sqrt{2\cdot\sqrt[3]{2^5}}=\sqrt{\sqrt[3]{2^5 \cdot 2^3}}=\sqrt{\sqrt[3]{2^8}}=\sqrt[6]{2^8}=\sqrt[6]{2^6 \cdot 2^2}=2 \cdot \sqrt[6]{2^2}=2 \sqrt[3]{2}](local/cache-vignettes/L568xH67/87b4a497e4067e31da4f23d15186c400-cc0ea.png?1688056140 "\sqrt{2\cdot\sqrt[3]{2^5}}=\sqrt{\sqrt[3]{2^5 \cdot 2^3}}=\sqrt{\sqrt[3]{2^8}}=\sqrt[6]{2^8}=\sqrt[6]{2^6 \cdot 2^2}=2 \cdot \sqrt[6]{2^2}=2 \sqrt[3]{2}")
Calcula y expresa el resultado simplificando al máximo:
– a) ![\sqrt[4]{2^8}](local/cache-vignettes/L43xH52/958d5a9486a65e52a1cf62ed5afb1996-cba4f.png?1688052540 "\sqrt[4]{2^8}"){kind=small}
– b) ![\sqrt[3]{1000}](local/cache-vignettes/L63xH50/1c79a157194d62190cf3182eef511dd9-88b5c.png?1688056140 "\sqrt[3]{1000}")
– c) ![\sqrt[3]{\sqrt{12}}](local/cache-vignettes/L57xH65/3eac1f375ebded72a54ef30de62177a1-131e8.png?1688052540 "\sqrt[3]{\sqrt{12}}")
– d) ![\sqrt{2\cdot\sqrt[3]{2^5}}](local/cache-vignettes/L80xH67/9d96ea621d857177678f99eb214e4545-20607.png?1688056140 "\sqrt{2\cdot\sqrt[3]{2^5}}")
– a)
– b)
– c)
– d)
Calcula y expresa el resultado simplificando al máximo:
– a)
– b)
– c)
– d)