radicales simplificar Martes 4 de abril de 2006, por dani | radicales simplificar_radicales Ejercicios_Resueltos – a) – b) – c) – d) Simplifica al máximo los siguientes radicales: – a) – b) – c) – d)
Matemáticas IES
![\sqrt[6]{125} = \sqrt[6]{5^3} = \sqrt{5}](local/cache-vignettes/L167xH52/22024ec59d8d0888625369fe36324178-2987a.png?1688111754 "\sqrt[6]{125} = \sqrt[6]{5^3} = \sqrt{5}")
![\sqrt[4]{6561}](local/cache-vignettes/L63xH50/a6ef3e2b0b49b3f4c7d5bde09b168951-be4da.png?1688108154 "\sqrt[4]{6561}")
![\sqrt[4]{6561} = \sqrt[4]{3^8} = \sqrt[4]{3^4 \cdot 3^4} = 3 \cdot 3 = 9](local/cache-vignettes/L313xH52/11f36f24cc334e88ec0956f5e5d49ffa-b6fbd.png?1688111754 "\sqrt[4]{6561} = \sqrt[4]{3^8} = \sqrt[4]{3^4 \cdot 3^4} = 3 \cdot 3 = 9")
![\sqrt[3]{18^3} = 18](local/cache-vignettes/L97xH52/cc249705e6de96eb553086c573986a09-bf9da.png?1688111754 "\sqrt[3]{18^3} = 18")
![\sqrt[5]{2 \cdot \sqrt[3]{2^{27}}} = \sqrt[5]{ \sqrt[3]{2^3 \cdot 2^{27}}} = \sqrt[5]{ \sqrt[3]{2^{30}}} = \sqrt[15]{2^{30}} = 2^2 = 4](local/cache-vignettes/L443xH67/a3dbd5e569cb6ab3d00f6c4fc08c1405-43919.png?1688111754 "\sqrt[5]{2 \cdot \sqrt[3]{2^{27}}} = \sqrt[5]{ \sqrt[3]{2^3 \cdot 2^{27}}} = \sqrt[5]{ \sqrt[3]{2^{30}}} = \sqrt[15]{2^{30}} = 2^2 = 4")
![\sqrt[6]{125}](local/cache-vignettes/L53xH50/5198fae7c5be01de79d979ae60e4817b-e326c.png?1688111754 "\sqrt[6]{125}")
![\sqrt[3]{18^3}](local/cache-vignettes/L53xH52/a0b4ecc5a0b9ae0ec9e6722d97b9504f-51b45.png?1688111754 "\sqrt[3]{18^3}")
![\sqrt[5]{2 \cdot \sqrt[3]{2^{27}}}](local/cache-vignettes/L87xH67/e1a71a8027cabee7a3482a6beac6af17-35cdf.png?1688111754 "\sqrt[5]{2 \cdot \sqrt[3]{2^{27}}}")