Sistema de ecuaciones con logaritmos 4564

, por dani

|

El ejercicio está resuelto en el siguiente vídeo

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are
\(x = -b \pm \sqrtb^2-4ac \over 2a.\)

Resuelve el siguiente sistema de ecuaciones:
\left\{ 2 \: \log \: x - \log \: y = 5 \atop \log (x \cdot y) = 4 \right.

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\)

P.-S.

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are
\(x = -b \pm \sqrtb^2-4ac \over 2a.\)